PokemonSqlLab/pokemon_sql/part2

#1-What are all the types of pokemon that a pokemon can have?
create schema pokemon;

select NAME
from pokemon.types

#2-What is the name of the pokemon with id 45?
create schema pokemon;

SELECT NAME
FROM pokemon.pokemons
WHERE id=45


#3-How many pokemon are there?

SELECT COUNT(id)
FROM pokemon.pokemons;

#4-How many types are there?

SELECT distinct(name)
FROM pokemon.types;


#5-How many pokemon have a secondary type?

SELECT COUNT(*)
FROM pokemon.pokemons
where secondary_type is not null

#6-What is each pokemon's primary type?

SELECT pokemons.name as Pokemon_Name,types.name as Primary_Name
from pokemon.pokemons, pokemon.types
where primary_type=types.id;

#7-What is Rufflet's secondary type?

SELECT types.name
from pokemon.pokemons, pokemon.types
where secondary_type=types.id
and pokemon.pokemons.name ="Rufflet";

#8-What are the names of the pokemon that belong to the trainer with trainerID 303?

select pokemons.name
from pokemon.pokemons, pokemon.pokemon_trainer
where pokemon_trainer.pokemon_id=pokemons.id
and  pokemon.pokemon_trainer.trainerID=303;

#9-How many pokemon have a secondary type Poison

SELECT count(*)
from pokemon.pokemons, pokemon.types
where secondary_type=types.id
and types.name="Poison";


#10-What are all the primary types and how many pokemon have that type?

select types.name, count(*)
from pokemon.pokemons, pokemon.types
where pokemons.primary_type=types.id
group by types.name;

#11-How many pokemon at level 100 does each trainer with at least one level 100 pokemone have? (Hint: your query should not display a trainer

SELECT COUNT(*),pokemon.pokemons.name
FROM pokemon.pokemon_trainer, pokemon.pokemons
WHERE pokemon.pokemon_trainer.pokemon_id= pokemon.pokemons.id
AND pokemon.pokemon_trainer.pokelevel= 100
GROUP BY name
HAVING COUNT(*) >= 1;

#12-How many pokemon only belong to one trainer and no other?

SELECT name, COUNT(DISTINCT pokemon.pokemon_trainer.trainerID)
FROM pokemon.pokemon_trainer, pokemon.pokemons
WHERE pokemon.pokemon_trainer.pokemon_id= pokemon.pokemons.id
GROUP BY name
HAVING COUNT(DISTINCT pokemon.pokemon_trainer.trainerID)=1;

#FINAL REPORT PART 4

SELECT pokemon.pokemons.name AS Pokemon_Name,pokemon.trainers.trainername AS Trainer_Name,pokemon.pokemon_trainer.pokelevel AS Level,PT.name AS Primary_Type, ST.name AS Secondary_Type
FROM pokemon.pokemon_trainer,pokemon.pokemons, pokemon.types AS PT ,pokemon.types AS ST,pokemon.trainers
WHERE pokemon.pokemons.id=pokemon.pokemon_trainer.pokemon_id
AND pokemon.pokemons.primary_type=PT.id
AND pokemon.pokemons.secondary_type=ST.id
AND pokemon.pokemon_trainer.trainerID=pokemon.trainers.trainerID
ORDER BY pokelevel DESC,
PT.name ASC , ST.name ASC, trainername asc ;
# The strongest trainer is the one who trains pokemon of highest level and then sorted in ascending order of primary level, secondary level and the trainer name
# Using above stated criterion the strongest trainer is - "Bandana Guy Kaler" as returned by above query as first record