PokemonSqlLab/Part3

Directions: Write a sql query or sql queries that can answer the following questions


* What is each pokemon's primary type?

        SELECT pokemon.pokemons.name, pokemon.types.name
        FROM pokemon.pokemons
        JOIN pokemon.types ON pokemons.primary_type = types.id;

* What is Rufflet's secondary type?

        SELECT pokemons.name, pokemons.secondary_type, types.name
        FROM pokemon.pokemons
        JOIN pokemon.types
        ON pokemons.secondary_type = types.id
        WHERE pokemons.name = "Rufflet";

* What are the names of the pokemon that belong to the trainer with trainerID 303?

        SELECT pokemons.name FROM pokemon.pokemons
        JOIN pokemon.pokemon_trainer
        ON pokemons.id = pokemon_trainer.pokemon_id
        WHERE pokemon_trainer.trainerID = 303;

* How many pokemon have a secondary type `Poison`

        SELECT pokemon.types.name, COUNT(pokemon.pokemons.name) AS "Count - Type Poison"
        FROM pokemon.pokemons
        JOIN pokemon.types
        ON pokemon.pokemons.secondary_type = pokemon.types.id
        WHERE pokemon.types.name = "Poison";

* What are all the primary types and how many pokemon have that type?

        SELECT pokemon.types.name, COUNT(pokemon.pokemons.name) AS "Count"
        FROM pokemon.pokemons
        JOIN pokemon.types
        ON pokemons.primary_type = types.id
        GROUP BY pokemon.types.id;

* How many pokemon at level 100 does each trainer with at least one level 100 pokemone have? (Hint: your query should not display a trainer

        SELECT COUNT(pokemon_trainer.pokemon_id)
        FROM pokemon.pokemon_trainer
        WHERE pokemon.pokemon_trainer.pokelevel = 100;

        ...Not sure how to answer the "each" part of the question without showing trainers. So below is an alternative response that shows "each" trainer by trainerID.

        SELECT COUNT(pokemon_trainer.pokemon_id)
        FROM pokemon.pokemon_trainer
        WHERE pokemon.pokemon_trainer.pokelevel = 100
        GROUP BY pokemon_trainer.trainerID;

* How many pokemon only belong to one trainer and no other?
  * the answer is 0.

        SELECT COUNT(pokemon.pokemon_trainer.pokemon_id)
        FROM pokemon.pokemon_trainer
        HAVING COUNT(pokemon_trainer.trainerID) = 1;