completed lab

Part 2

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+CREATE SCHEMA pokemon;
+
+
+## PART 2 ##
+#what are all the types of pokemon that a pokemon can have?
+SELECT name FROM pokemon.types;
+
+#What is the name of the pokemon with id 45?
+SELECT name FROM pokemon.pokemons WHERE id = 45;
+
+#How many pokemon are there?
+SELECT COUNT(*) FROM pokemon.pokemons;
+
+#How many types are there?
+SELECT COUNT(*) FROM pokemon.types;
+
+#How many pokemon have a secondary type?
+SELECT COUNT(secondary_type) FROM pokemon.pokemons;
+CREATE SCHEMA pokemon;

Part 3

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+### PART 3 ###
+#each pokemons primary type
+SELECT p.name, pt.name
+FROM pokemon.pokemons p
+JOIN pokemon.types pt
+ON pt.id = p.primary_type;
+
+#What is Rufflet's secondary type
+SELECT p.name, t.name
+FROM pokemon.pokemons p
+JOIN pokemon.types t
+ON p.secondary_type = t.id WHERE p.name = "rufflet";
+
+#what are the names of the pokemon that belong to the trainer with the trainerID 303?
+SELECT p.name
+FROM pokemon.pokemons p
+JOIN pokemon.pokemon_trainer ptrain
+ON ptrain.pokemon_id = p.id WHERE ptrain.trainerID = 303;
+
+#How many pokemon have a secondary type Poison
+SELECT count(p.secondary_type)
+FROM pokemon.pokemons p
+JOIN pokemon.types pt
+ON p.secondary_type = pt.id WHERE pt.name = "poison";
+
+#What are all the primary types and how many pokemon have that type?
+SELECT pt.name , count(pt.id) AS "Number of pokemon"
+FROM pokemon.pokemons p
+JOIN pokemon.types pt
+ON p.primary_type = pt.id
+GROUP BY pt.name;
+
+#how many pokemon at level 100 does each trainer with at least one level 100 pokemon have?
+#hint: your query should not display a trainer
+SELECT count(ptrain.pokelevel) AS "number of pokemon above 100 for each trainer with at least one pokemon above 100"
+FROM pokemon.pokemon_trainer ptrain
+WHERE ptrain.pokelevel = 100
+GROUP BY ptrain.trainerID;
+
+#how many pokemon only belong to one trainer and no other?
+SELECT COUNT(*) as "UniquelyOwned"
+FROM (SELECT DISTINCT pokemon_id, COUNT(pokemon_id)
+      FROM pokemon.pokemon_trainer
+      GROUP BY pokemon_id
+      HAVING COUNT(DISTINCT trainerID) = 1) alias;

Part 4

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+
+#### PART 4 ####
+#Write a query that returns the following columns: Pokemon Name, Trainer Name, Level
+#                                                     Primary Type, Secondary Type
+#it ranks the trainers based on their pokemons level
+
+
+SELECT poke.name as "Pokemon Name", pt.trainername as "Trainer Name", ptrain.pokelevel as "Level",
+       ptypes.name as "Primary Type", ptypes2.name as "Secondary Type"
+FROM pokemon.pokemons poke
+JOIN pokemon.pokemon_trainer ptrain ON ptrain.pokemon_id = poke.id
+JOIN pokemon.types ptypes ON poke.primary_type = ptypes.id
+join pokemon.types ptypes2 ON poke.secondary_type = ptypes2.id
+join pokemon.trainers pt ON ptrain.trainerID = pt.trainerID
+ORDER BY ptrain.pokelevel;
+